algebra

sqr root of 3a + 9(sqr root of 27a^3)

asked by Gabby
  1. √27a^3 = 3a√3a
    so
    √(3a) + 9√(27a^3)
    = √(3a) + 27a√(3a)
    = √(3a)( 1 + 27a)

    not much gained here, poor question if the instructions were to "simplify"

    posted by Reiny

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