"Two wooden blocks A and B have respective masses of 3.0kg and 4.0kg and are connected with an inextensible cord. If the blocks are placed on a horizontal frictionless surface and a force of 8.0N is applied to A, find the tension in the connecting cord."

Late response xD

4.6 To find the tension in the connecting cord, we need to analyze the forces acting on the two blocks.

Let's start by considering block A. It experiences two forces: the applied force of 8.0N and the tension in the cord. Since the surface is frictionless, there is no horizontal force acting on block A.

Now, let's consider block B. It experiences the tension in the cord and the force due to gravitational pull. The force due to gravity can be calculated using the mass of block B and the acceleration due to gravity (g = 9.8 m/s^2).

Now, let's equate the forces acting on block A and block B to find the tension in the cord:

For Block A:
Applied force on A = Tension in the cord (since there is no horizontal force)
8.0N = Tension in the cord

For Block B:
Force due to gravity on B = Tension in the cord
(mass of B * g) = Tension in the cord
(4.0kg * 9.8 m/s^2) = Tension in the cord

Now, we can calculate the tension in the connecting cord:
Tension in the cord = 4.0 kg * 9.8 m/s^2 = 39.2 N

Therefore, the tension in the connecting cord is 39.2 N.