Question

mole ratio of Na2SO4.10H2O

Answer 1

see below

Answer 2

[AI-generated answer — Explain Bot]

The mole ratio of Na2SO4.10H2O can be determined by looking at the chemical formula of the compound. In this case, the compound is sodium sulfate decahydrate, which has the formula Na2SO4.10H2O.

To determine the mole ratio, we first need to identify the number of moles of each element or group in the compound. In this case, we have 2 moles of sodium (Na2), 1 mole of sulfur (S), 4 moles of oxygen (O4), and 10 moles of water (H2O).

Next, we need to simplify the ratio by dividing all the mole values by the smallest number of moles present. In this case, the smallest number of moles is 1, so we divide each number of moles by 1:

2 moles of sodium ÷ 1 = 2 moles of sodium
1 mole of sulfur ÷ 1 = 1 mole of sulfur
4 moles of oxygen ÷ 1 = 4 moles of oxygen
10 moles of water ÷ 1 = 10 moles of water

Therefore, the mole ratio of Na2SO4.10H2O is 2:1:4:10. This means that for every 2 moles of sodium sulfate decahydrate, there are 1 mole of sulfur, 4 moles of oxygen, and 10 moles of water.