The reaction of a metal ion, M^2+, with EDTA is given in the following equation:
M^2+(aq) + Y^4-(aq) <==> MY^2-(aq)
The EDTA was standardized with a 0.04 M Zn^2+ solution. 25.05 mL of EDTA solution was used to titrate the Zn^2+ solution. From this standardization, calculate the concentration of the EDTA solution.
Thanks in advance!
25.05 mL EDTA x M EDTA = ?mL Zn x 0.04 M Zn.
You didn't post the mL of the Zn solution used. Plug into the equation above and solve for M EDTA.
Oh, the wonderful world of chemistry titrations! Let's calculate that concentration for you.
So, we know that 25.05 mL of EDTA solution (let's call it V1) was used to titrate the Zn^2+ solution.
We also know that the concentration of the Zn^2+ solution (let's call it C1) is 0.04 M.
The equation tells us that the stoichiometry between the metal ion M^2+ and EDTA is 1:1. So, the moles of Zn^2+ in the titrated solution is the same as the moles of EDTA used.
The moles of Zn^2+ (n1) can be calculated as:
n1 = C1 * V1
Now, we need to know the stoichiometry between Y^4- and EDTA. From the equation, we see that it's 1:1 as well.
Assuming that the reaction went to completion, we can say that the moles of Zn^2+ in the titrated solution is the same as the moles of MY^2- formed.
So, the moles of MY^2- (n2) is also n1.
We can calculate the moles of MY^2- using the concentration of the EDTA solution (let's call it C2) and its volume (let's call it V2). Since we know that the stoichiometry is 1:1, we get:
n2 = C2 * V2
Since moles are equal, we can equate n1 and n2:
C1 * V1 = C2 * V2
Now we can rearrange the equation to solve for C2 (the concentration of the EDTA solution):
C2 = (C1 * V1) / V2
Plugging in the values we know:
C2 = (0.04 M * 25.05 mL) / V2
And voila! You have the concentration of the EDTA solution. Just divide the moles of Zn^2+ (which is equal to the moles of MY^2-) by the volume of the EDTA solution used.
Hope that helps! And remember, chemistry is all about finding the right balance. Just like a good joke! Keep laughing!
To calculate the concentration of the EDTA solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of Zn^2+ solution
V1 = volume of Zn^2+ solution used
M2 = concentration of EDTA solution (what we want to find)
V2 = volume of EDTA solution used
Given:
M1 = 0.04 M
V1 = volume of Zn^2+ solution used = 25.05 mL = 0.02505 L
V2 = volume of EDTA solution used = 0.025 L (assuming it's the same volume as the Zn^2+ solution used)
Substituting the values into the equation:
(0.04 M)(0.02505 L) = M2(0.025 L)
0.001002 = 0.025M2
Solving for M2:
M2 = 0.001002 / 0.025
M2 = 0.04008 M
Therefore, the concentration of the EDTA solution is approximately 0.04008 M.
To calculate the concentration of the EDTA solution, we can use the equation of the reaction between the metal ion and EDTA given in the problem.
The reaction equation is:
M^2+(aq) + Y^4-(aq) <==> MY^2-(aq)
In the equation, M^2+ represents the metal ion and Y^4- represents the EDTA (ethylenediaminetetraacetic acid) molecule. MY^2- represents the complex formed between the metal ion and EDTA.
The problem states that the EDTA solution was standardized with a 0.04 M Zn^2+ (zinc) solution. This means that the concentration of zinc ion is 0.04 moles per liter (M).
Next, the problem states that 25.05 mL of the EDTA solution was used to titrate the zinc solution.
To calculate the concentration of the EDTA solution, we can use the stoichiometry of the reaction. The mole ratio between zinc ion (Zn^2+) and EDTA is 1:1. This means that for every 1 mole of zinc ion, we need 1 mole of EDTA.
First, we need to convert the volume of the EDTA solution used in the titration to liters:
25.05 mL = 25.05 mL * (1 L / 1000 mL) = 0.02505 L
Next, we use the equation:
C1V1 = C2V2
where C1 is the concentration of the zinc solution, V1 is the volume of zinc solution, C2 is the concentration of the EDTA solution, and V2 is the volume of the EDTA solution used in the titration.
Substituting the values:
(0.04 M)(0.02505 L) = C2(0.02505 L)
C2 = (0.04 M)(0.02505 L) / 0.02505 L
C2 = 0.04 M
Therefore, the concentration of the EDTA solution is 0.04 M.