Fe + 2HCl = FeCl2 + H2 A piece of metallic iron (10 moles) was dissolved in concentrated hydrochloric acid. The reaction formed hydrogen gas and iron chloride. How many grams of HCl were consumed? Don't forget the units.

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You have the equation.

Using the coefficients in the balanced equation, convert 10 mols Fe to moles HCl.
Now convert moles HCl to grams. g = moles x molar mass.

To find the number of grams of HCl consumed, we need to use the balanced equation for the reaction.

Fe + 2HCl → FeCl2 + H2

From the equation, we can see that 1 mole of Fe reacts with 2 moles of HCl. Therefore, to calculate the moles of HCl, we'll use the mole ratio with respect to the moles of Fe.

Given that the amount of Fe is 10 moles, we can calculate the moles of HCl consumed using the ratio:

10 moles Fe × (2 moles HCl / 1 mole Fe) = 20 moles HCl

Now, to convert moles of HCl into grams, we need to use its molar mass. The molar mass of HCl is approximately 36.5 g/mol.

20 moles HCl × 36.5 g/mol = 730 grams HCl

Therefore, 730 grams of HCl were consumed in the reaction.

To determine the number of grams of HCl consumed in the reaction, we need to use the balanced chemical equation and the stoichiometry of the reaction.

The balanced chemical equation is:
Fe + 2HCl -> FeCl2 + H2

From the equation, we can see that one mole of iron (Fe) reacts with two moles of hydrochloric acid (HCl) to produce one mole of iron chloride (FeCl2) and one mole of hydrogen gas (H2).

Given the information that 10 moles of iron reacted, we can calculate the corresponding amount of HCl consumed.

Using the stoichiometry of the reaction, we know that for every 2 moles of HCl consumed, there is 1 mole of Fe. Therefore, we can set up a proportion:

(2 moles HCl / 1 mole Fe) = (x moles HCl / 10 moles Fe)

Solving for x, we find:
x moles HCl = (2 moles HCl / 1 mole Fe) * 10 moles Fe = 20 moles HCl

Now, we need to convert moles of HCl to grams. The molar mass of HCl is approximately 36.46 g/mol.

Mass of HCl = moles of HCl * molar mass of HCl
Mass of HCl = 20 moles HCl * 36.46 g/mol = 729.2 grams of HCl

Therefore, approximately 729.2 grams of HCl were consumed in the reaction.