mat 101

Equation for a line that passes through (6,26) and has a slope of 3

Equation for a line that passes through the points (5,5) and (10,20)

Equation for a line that passes through (9,25) and has a slope of -3.

Equation for a line that passes through (1,) and is perpendicular to the line 4x+6y=18.

Equatuion for a cirle with a radius of 4 and a midpoint at (2,2).

asked by keith
  1. I already know how to do these. Try them yourself first and show me where you got stuck.

    The first three can all be done substituting in
    y = m x + b
    where m is the slope.

    For the fourth one, put the equation in form y = m x + b first
    Then find m' = -1/m
    That is the slope of a line perpendicular to the original one
    then do y = m'x + b and substitute in your point, which you forgot to type the y coordinate for.

    In the last one a circle equation is of form
    (x-k)^2 + (y-h)^2 = r^2
    where (k,h) is the center and r is the radius.

    posted by Damon
  2. y=mx+b

    26=3(6)+b
    b=26/18
    b=13/9

    posted by Anonymous

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