Earl N. Meyer found that it took 26.54 mL of a 0.0100 M KOH solution to reach the equivalence point for the titration of 25.00 mL of HCL. What is the molarity of the HCL?
mLNaOH x M NaOH = mLHCl x M HCl
Solve for the one unknown.
Where do I get the variable from? Where does NaOH come from?
First off, I wrote NaOH instead of KOH.
mL KOH = 26.54
M KOH = 0.0100
mL HCl = 25.00
M HCl = ??
0.01062M
To find the molarity of the HCL solution, we can use the concept of stoichiometry in a titration. Let me explain step-by-step how to calculate the molarity of the HCL solution based on the given information.
Step 1: Write the balanced chemical equation for the reaction between HCL and KOH:
HCl + KOH → KCl + H2O
Step 2: Determine the stoichiometric ratio between HCl and KOH from the balanced equation. In this case, the ratio is 1:1.
Step 3: Calculate the number of moles of KOH used in the reaction using the formula:
moles of KOH = Molarity of KOH solution × Volume of KOH solution (in liters)
Given that the KOH solution has a molarity of 0.0100 M and a volume of 26.54 mL (which needs to be converted to liters), we have:
Volume of KOH solution = 26.54 mL = 0.02654 L
moles of KOH = 0.0100 M × 0.02654 L = 0.0002654 mol
Step 4: Use the stoichiometric ratio to determine the number of moles of HCl reacted. In this case, the ratio is 1:1.
moles of HCl = 0.0002654 mol
Step 5: Calculate the molarity of HCl using the formula:
Molarity of HCl = moles of HCl / Volume of HCl solution (in liters)
Given that the volume of HCl solution is 25.00 mL (which needs to be converted to liters), we have:
Volume of HCl solution = 25.00 mL = 0.02500 L
Molarity of HCl = 0.0002654 mol / 0.02500 L = 0.0106 M
Therefore, the molarity of the HCl solution is 0.0106 M.