how do you find the moles of solute and the molarity if the molar mas is 98.07, mass of solute is 62.0, and the volume of solution is 1.00?
moles = grams/molar mass
M = moles/L
To find the moles of solute, you can use the formula:
moles of solute = mass of solute / molar mass
Given that the molar mass is 98.07 g/mol and the mass of the solute is 62.0 g, we can substitute these values into the formula:
moles of solute = 62.0 g / 98.07 g/mol
Dividing these values gives:
moles of solute ≈ 0.632 mol
Now, to find the molarity, you can use the formula:
molarity = moles of solute / volume of solution
Given that the volume of the solution is 1.00 L (which is equivalent to 1.00 dm³), and we previously found that the moles of solute are approximately 0.632 mol, we can substitute these values into the formula:
molarity = 0.632 mol / 1.00 dm³
Thus, the molarity is:
molarity ≈ 0.632 mol/dm³ (or M)
Therefore, the moles of solute are approximately 0.632 mol, and the molarity is approximately 0.632 mol/dm³ (or M).