Chemistry

What volume of 0.123 M AgNO3(aq) is needed to form 0.657 g of AgCl(s)?

0.564 mL.
18.6 mL.
37.2 mL.
1.77 L.

asked by Kelly
  1. Write the equation.
    AgNO3 ==> AgCl (obviously 1 mol AgNO3 is need to form 1 mole AgCl).

    0.657 g AgCl is how many moles? moles = g/molar mass = ??

    moles AgCl = moles AgNO3.

    Molarity = moles/L.
    You know molarity and moles, solve for L.

    posted by DrBob222

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