What volume of 0.123 M AgNO3(aq) is needed to form 0.657 g of AgCl(s)?
Write the equation.
AgNO3 ==> AgCl (obviously 1 mol AgNO3 is need to form 1 mole AgCl).
0.657 g AgCl is how many moles? moles = g/molar mass = ??
moles AgCl = moles AgNO3.
Molarity = moles/L.
You know molarity and moles, solve for L.posted by DrBob222