What is the maximum yield of NH3 that can be formed from 8.50 grams of N2 and 1.00 grams of H2 in the (balance) reaction N2 + 3H2---- 2NH3?
Balance the equation.
Convert 8.50 g N2 to mols. Mols = grams/molar mass.
Convert 1.00 g H2 to mols.
Using the coefficients in the balanced equation, convert mols H2 and mols N2 to mols NH3.
The correct answer for mols NH3 will be the smaller of the two answera you obtain.
Convert mols NH3 to grams.
Post your work if you get stuck.
im stuck can you help me. my chemical makeup is C08sixty^ can you make me equilibrium with the answer to the equation. if this is ok please
To determine the maximum yield of NH3 that can be formed, we need to calculate the limiting reactant first. The limiting reactant is the reactant that is completely consumed in the reaction and determines the amount of product that can be formed.
First, we need to convert the given masses of N2 and H2 to moles using their molar masses. The molar mass of N2 is 28.02 g/mol, and the molar mass of H2 is 2.02 g/mol.
Moles of N2 = 8.50 g / 28.02 g/mol ≈ 0.303 mol
Moles of H2 = 1.00 g / 2.02 g/mol ≈ 0.495 mol
Next, we calculate the stoichiometric ratio between N2 and NH3 using the balanced equation: N2 + 3H2 → 2NH3. From the equation, we can see that 1 mole of N2 produces 2 moles of NH3.
Therefore, moles of NH3 that can be produced from N2 = 0.303 mol × (2 mol NH3 / 1 mol N2) ≈ 0.606 mol
Now, we calculate the stoichiometric ratio between H2 and NH3. From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3.
Therefore, moles of NH3 that can be produced from H2 = 0.495 mol × (2 mol NH3 / 3 mol H2) ≈ 0.330 mol
Comparing the moles of NH3 that can be produced from N2 (0.606 mol) and H2 (0.330 mol), we can see that the limiting reactant is H2, as it produces fewer moles of NH3.
Finally, we calculate the maximum yield of NH3 using the moles of the limiting reactant and the stoichiometric ratio:
Maximum yield of NH3 = 0.330 mol × (17.03 g/mol) ≈ 5.62 g
Therefore, the maximum yield of NH3 that can be formed is approximately 5.62 grams.