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Algebra
Factor out 8x^3y^6 + 27 One factor is 2xy^2+3. (The sum of the cube roots of the first and last terms). Use long division to compute (8x^3y^6 + 27)/(2xy^2 + 3) to get the other factor
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Algebra (new one since I put "match" (bad speller)
I have a few match problems that I can't figure out. 1.solve: 3x+5=x√7 (that's a radical sign) 2.factor: (2k+3)2(2x+3)(y2)20(y2)2 (the "2" after (2k+3) ans (y2) is suppose to be a square sign. thanks if you can help, or
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factor completely. remember to look first for a common factor. if a polynomial is prime state this. x^2+2xy+y^29
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factor the polynomial completely: 2xy3y40x+60 2xy40x3y+60 2x(y20)3(y20) (2x3)(y20)
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Use Pascal's triangle to expand the expression. (x − y)5 so I tried to work this out: (xy)^5 = [(xy)(xy)][(xy)(xy)](xy) (xy)^2 = (xy)(xy) = x^2  2xy + y^2 x^2  2xy + y^2)(x^2  2xy + y^2) = x^4 4x^3y + 6x^2y^2 
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Simplify (2xy^2+3)((2xy^2)^2(2xy^2)(3)+(3)^2) This reminds me of (U+a)(U^2 aU + a^2). When mulipltiplied out, one gets a cubic equation. Do you remember the formula for factoring the sum of two cubes? a^3+b^3= ????
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factor 2x3y2+12xydivided by 2xy Divide 2xy into each term, term by term. xy+6
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I thought number 4 on this list was incorrect but didn't know how to fully explain it here is the list that I have. Please look at the following simplification of an algebraic expression. Which line contains the mistake and why?
asked by Linda on March 8, 2013 
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Can 2xy  y  1 be factored out? How? about all you can do is take the common y out of the first two terms; that in itself is not much help. dont know if this is rite or not..but just a guess.. assuming 2xy  y  1 = 0 2xy  y = 1
asked by Sarah on August 15, 2007 
algebra
Factor: 2xy + 6x  4y  12 a)(2x + 4) (y + 3) b)(2x  4) (y + 3)^2 c)(2x  4) (y  3) d)(2x  4) (y + 3)
asked by ant on June 2, 2010