algebra

8y^3-27
8y(y^2-27)

x^2+36=
(x+6)(x+6)

Facatoring completely
are they right. corrected if wrong

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  1. The first one is the difference of cubes
    a^3 - b^3 = (a-b)(a^2 + ab + b^2)

    so
    8y^3 - 27
    = (2y-3)(4y^2 + 6y + 9)

    the second doesn't factor over the real numbers.

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    posted by Reiny

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