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Chemistry--help!
Given the equilibrium: HCN(aq) + H2O(l) ←→ H3O+(aq) + CN-(aq) ΔH >0; Ka = 4.0 x10-10 What happens to the concentration of hydrogen cyanide [HCN] when the following stresses are placed on the system at equilibrium? NaCl is
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Chemistry
Indicate which of the following has the highest entropy at 298 K. 0.5 g of HCN 1 mol of HCN 2 kg of HCN 2 mol of HCN All of the above have the same entropy at 298 K.
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chem
Calculate the pH of 0.20 M NaCN solution. NaCN ---> Na+ + CN- CN- + H20+ ---> HCN+ + OH- Initial conc. of CN- = 0.20 mol/L change = -x equillibrium = 0.20-x HCN equill. = +x OH equill. = 1x10^-7+x Ka= 6.2 x 10^-10 Kb = KW/Ka =
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chem
the solution with the lowest pH is A. 1.0 M HF B. 1.0 M HCN C. 1.0 M HCOOH D. 1.0 M CH3COOH and how did you find it?
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Analytical Chem
Determine [Zn2 ], [CN–], and [HCN] in a saturated solution of Zn(CN)2 with a fixed pH of 2.390. The Ksp for Zn(CN)2 is 3.0 × 10–16. The Ka for HCN is 6.2 × 10–10. I know the following is what needs to be done, but im
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chemistry
calculate the pH of a 0.50 m solution of HCN. Ka for HCN is 4.9*10^-10 (The chemical equation for this.)
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Quantitative Chemistry
Ignoring activities, determine the molar solubility (S) of Zn(CN)2 in a solution with a pH = 2.92. Ksp (Zn(CN)2) = 3.0 × 10-16; Ka (HCN) = 6.2 × 10-10. Completely lost!
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chemisrty
Rank following acids frommost to least acidic: hydrocyanic acid (HCN) Ka = 6.2 × 10−10 hypoiodous acid (HOI) Ka = 2 × 10−11 chlorous acid (HClO2) Ka = 1.2 × 10−2 acetic acid (CH3COOH) Ka = 1.8 × 10−5 1. HOI > HClO2 >
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Chem 2
Which solution will have the lowest pH ? A. .10 M HCN B. .10 M HNO3 C. .10 M NaCL D. .10 M H2CO3 E. .10 M NaOH
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Chemistry
Which solution will have the lowest pH? a. 0.10 M HClO2, pKa = 1.96 b. 0.10 M HCN, pKa = 9.21 c. 0.10 M HF, pKa = 3.19 d. 0.10 M HClO, pKa = 7.538 e. 0.00010 M HCl Does the lower the pka stronger the acid, means the lower the ph,
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Chemistry
Hydrogen cyanide is a highly poisonous, volatile liquid. It can be prepared by the following reaction. CH4(g) + NH3(g) → HCN(g) + 3 H2(g) What is the heat of reaction at constant pressure? Use the following thermochemical
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Chemistry
Calculate the pH of the solution resulting from the addition of 75.0 mL of 0.15 M KOH to 35.0 mL of 0.20 M HCN (Ka (HCN) = 4.9 × 10–10) My answer is 9.52, but im not sure.
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