A group of 45 tokens is arranged into three piles such that each pile contains a different prime number of tokens. What is the greatest number of tokens possible in any of the three piles?

Thanks

37 + 3 + 5 = 45

45 divided by three is 15!

A group of 45 tokens is arranged into three piles such that EACH PILE CONTAINS A DIFFERENT PRIME NUMBER OF TOKENS.

What is the greatest number of tokens possible in any of the three piles?

37 RESULTING IN 37 + 3 + 5 = 45.

45 To find the greatest number of tokens possible in any of the three piles, we need to identify the largest prime number less than or equal to 45.

First, let's list the prime numbers less than or equal to 45:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43

From this list, we can see that the greatest prime number less than or equal to 45 is 43. Therefore, the greatest number of tokens possible in any of the three piles is 43.

If you ever need to find prime numbers, you can start by checking if the number is divisible by 2. If not, you can continue checking if it's divisible by odd numbers (starting from 3) up to the square root of the number. If it's not divisible by any of these numbers, then it is a prime number.

I hope this explanation has helped. Let me know if you have any further questions!