physical science

What will the stopping distance be for a 1,000-kg car if -2,000 N of force are applied when the car is traveling 10 m/s?

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asked by joe
  1. The deceleration rate will be
    a = F/m = 2 m/s^2. The time to stop is given by
    t = Vo/a = (10 m/s)/(2m/s^2) = 5 s

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    posted by drwls
  2. calculate the KE of a 1500 kg. car travelling at 60 km/h

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    posted by joe
  3. 45000j

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    posted by jim

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