A baby rabbit moves 5 inches forward with each hop and his mother moves 14 inches forward with each hop. After the mother and baby each hop 10 hops in the same direction, the mother stops and waits for her baby to catch up. How many hops does the baby have to take to catch up?
5 inches x 10 hops= 50 inches
14 inches x 10 hops= 140 inches
140 inches-50 inches= 90 inches
so, the baby has to travel 90 more inches to catch up to his mom, if he travels 5 inches per hop, how many more will it take??
Hopefully you can continue from here, if not let me know.
~aShLeY
To find out how many hops the baby rabbit needs to take to catch up with its mother, we first need to calculate the distance covered by each rabbit after 10 hops.
The baby rabbit moves 5 inches forward with each hop, so the total distance covered by the baby rabbit after 10 hops is:
5 inches/hop * 10 hops = 50 inches
Similarly, the mother rabbit moves 14 inches forward with each hop, so the total distance covered by the mother rabbit after 10 hops is:
14 inches/hop * 10 hops = 140 inches
Now, we need to find the difference in distance between the mother and the baby rabbits. The mother is ahead by:
140 inches - 50 inches = 90 inches
Since each hop is the same for both the baby and mother, the baby needs to take:
90 inches / 5 inches/hop = <<90/5=18>>18 hops
Therefore, the baby rabbit needs to take 18 hops to catch up with its mother.