Algebra II

An airplane leaves airport A and flies 200 km. At this time its bearing from Airport B, 250 km to the west, is 120 degrees. How far is the airplane from B?

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  1. let the plane's position be P
    so in triangle ABP, angle A = 30° ( a bearing of 120 = 90+30)
    let's find angle P
    sinP/250 = sin 30/200

    (case 1)
    angle P = 38.682
    then angle A = 113.328°
    BP/sin113.328 = 200/sin30
    BP = 372.63 km

    case 2
    angle P = 141.318
    then angle A = 8.682°
    BP/sin8.682 = 200/sin30
    BP = 60.38 km

    both answers make sense, since the triangle results in the "ambiguous case"

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  2. 1. A passenger in an airplane at an altitude of 10 km sees two towns to the east of the plane. The angle of depression to town A is 28o and the angle of depression to town B is 55o. How far apart are the two towns?

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