Physics

University students, studying the activity of a particular radioactive isotope which had a half-life of 12.0 hours. If the original activity of the sample was 448 kBq, what would the activity be 3.00 days later?

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  1. Three days is six 12-hour intervals, which is six half-lives.

    Multiply the original activity by (1/2)^6 = 1/64

    448/64 =__ kBq

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    posted by drwls

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