statistics

assume the body temperature of healthy adults distributed with a mean of 98.20F and a standard deviation of 0.62F. If you have a body temperature of 99.00F, what is your percentile score?

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  1. Z = (x-mean)/SD

    Insert values and solve for Z.

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to that Z score.

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    posted by PsyDAG
  2. 99.0-98.2/0.62
    Answer = 1.29


    Is this correct?

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