9.50mL of .100M NaOH + 8.00mL of .100M of HC2H3O2. Find the pH.

Okey this is what I did.

8.00-9.50=1.5mL or .0015L

.0015L x .1000 = .00015 moles

.00015/(total volume) = .0085714 M

-log(.0085714)= 2.0669=pOH
14-2.0669 = 11.933

But I'm getting the feeling that this is wrong. Thanks.

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  1. That looks ok to me except you didn't label 11.93 s the pH. If you find differently, please let me know.

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