how many grams of silver chloride are produced when 45 grams of calcium chloride react with excess silver nitrate?
its 110
To determine the number of grams of silver chloride produced, we need to use the balanced chemical equation for the reaction between calcium chloride (CaCl2) and silver nitrate (AgNO3).
The balanced chemical equation for the reaction is as follows:
CaCl2 + 2 AgNO3 -> 2 AgCl + Ca(NO3)2
From the balanced equation, we can see that 1 mole of calcium chloride (CaCl2) reacts with 2 moles of silver nitrate (AgNO3) to produce 2 moles of silver chloride (AgCl).
First, we need to calculate the number of moles of calcium chloride (CaCl2) present using its molar mass. The molar mass of calcium chloride is 40.08 g/mol for calcium (Ca) and 35.45 g/mol for chlorine (Cl).
Number of moles of CaCl2 = Mass of CaCl2 / Molar mass of CaCl2
= 45 g / (40.08 g/mol + 2 * 35.45 g/mol)
= 45 g / 111.98 g/mol
≈ 0.4015 moles
Next, we determine the number of moles of silver chloride (AgCl) produced using the mole ratio from the balanced equation. Since 1 mole of calcium chloride reacts to produce 2 moles of silver chloride:
Number of moles of AgCl = 2 * Number of moles of CaCl2
= 2 * 0.4015 moles
= 0.803 moles
Finally, we can calculate the mass of silver chloride (AgCl) using its molar mass. The molar mass of silver chloride is the sum of the atomic masses of silver (Ag) and chlorine (Cl), which is 107.87 g/mol for silver (Ag) and 35.45 g/mol for chlorine (Cl).
Mass of AgCl = Number of moles of AgCl * Molar mass of AgCl
= 0.803 moles * (107.87 g/mol + 35.45 g/mol)
= 0.803 moles * 143.32 g/mol
≈ 115.15 grams
Therefore, approximately 115.15 grams of silver chloride (AgCl) will be produced when 45 grams of calcium chloride (CaCl2) reacts with excess silver nitrate (AgNO3).
180 AgCl?
This is a basic stoichiometry problem.
1. Write and balance the equation.
2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2
2. Convert what you have, in this case 45 g CaCl2, to moles. moles = grams/molar mass = 45/molar mass CaCl2 = ?? moles CaCl2
3. Using the coefficients in the balanced equation, convert moles of what you have (CaCl2) to moles of what you want (in this case moles AgCl).
??moles CaCl2 x (2 moles AgCl/1 mole CaCl2) = ??moles x (2/1) = xx moles AgCl
4. Now convert moles AgCl to grams. g = moles x molar mass.