how many grams of silver chloride are produced when 45 grams of calcium chloride react with excess silver nitrate?

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  1. This is a basic stoichiometry problem.

    1. Write and balance the equation.
    2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2

    2. Convert what you have, in this case 45 g CaCl2, to moles. moles = grams/molar mass = 45/molar mass CaCl2 = ?? moles CaCl2

    3. Using the coefficients in the balanced equation, convert moles of what you have (CaCl2) to moles of what you want (in this case moles AgCl).
    ??moles CaCl2 x (2 moles AgCl/1 mole CaCl2) = ??moles x (2/1) = xx moles AgCl

    4. Now convert moles AgCl to grams. g = moles x molar mass.

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  2. 180 AgCl?

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