How many grams of chromium are needed to react with an excess of CuSo4 tp produce 27 g Cu?

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  1. Just so the chem teachers know what your school subject is...

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  2. 1. Write the equation and balance it.
    2. Convert 27 g Cu to moles. moles = grams/molar mass.
    3. Using the coefficients in the balanced equation, convert moles Cu to moles Cr.
    4. Now convert moles Cr to grams. g = moles x molar mass.

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  3. 14.7

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  4. help w this pls

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  5. Solution:
    The chemical equation for this reaction is: 3CuSO4 + 2Cr = Cr2(SO4)3 + 3Cu
    The amount of Cu produced in reaction is n(mol) = m(g) / MW(g/mol)
    n(Cu) = 27 / 63.5 = 0.425 mol
    According to the chemical equation n(Cr) = 2⁄3 ∙ n(Cu)
    n(Cr) = 2⁄3 ∙ 0.425 = 0.283 mol
    The mass of Cr is
    m(g) = n(mol) ∙ MW(g/mol)
    The molar weight of Cr is equal to its atomic weight in the periodic table of elements (MW(Cr) = 52 g/mol)
    m(Cr) = 0.283 ∙ 52 = 14.7 g Answer: m(Cr) = 14.7 g

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