The density of 3M solution of NaCl is 1.25 g/mL. Calculate the molality of the soution.

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  1. 3 M solution means 3 moles solute/L soln.
    The soln density is 1.25 g/mL; therefore, 1000 mL soln x 1.25 g/L = 1250 grams for the soln. Part of the 1250 g is water, part NaCl. Since it is 3 moles, that is 3 moles x 58.44 g/mol =175.33 g NaCl. Thus the water portion is 1250-175.33 = ??
    Then 3 moles/kg solvent = m

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  2. suppose you mix 15 g of Na2SO4 and 7.5g of C.Which is the limiting reaction

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