Physics difficult... chris help again plz.

A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is an isothermal (constant temperature) compression at 300 K. (Note that the diagram is illustrating V vs P. This should make no difference in your calculations. )

i found the pressure at point C to be .4 atm and the heat exhausted from B to C to be 6000J

also on the picture it shows from C to A T=300[k]


If the net work done by the engine per cycle is 480 J, find the work done by the gas during process C to A??.

i got -5681 but that isn't right

* Physics - Chris, Friday, May 7, 2010 at 8:29pm

pA = pB = 2 atm = 2 * 101325 Pa = 202650 Pa
vA = 1 L = 1 * 10^-3 m^3
vB = 5 L = 5 * 10^-3 m^3
W(A to B) = 202650 * (5 * 10^-3 - 1 * 10^-3) = 202650 * 4 * 10^-3 = 810.6 J
W(B to C) = 0 (because volume is constant)
W(in complete cycle) = 480 J

W(in complete cycle) = W(A to B) + W(B to C) + W(C to A)
480 = 810.6 + 0 + W(C to A)
W(C to A) = 480 - 810.6 = -330.6 J
Ans: -330.6 J


That isn't the right answer either.

  1. 👍 0
  2. 👎 0
  3. 👁 124
asked by Jason

Respond to this Question

First Name

Your Response

Similar Questions

  1. Physics

    A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is

    asked by Jason on May 7, 2010
  2. Physics

    A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is

    asked by Jason on May 8, 2010
  3. Physic II

    a carnot heat engine operates between reservoirs at 550K and 300K, discarding 1500J of heat in each cycle. A) What is the engine's efficiency? B) How much heat is supplied to the engine by the hot reservoir in each cycle?

    asked by rujiye on April 30, 2014
  4. Physics (Heat Engines)

    21. A heat engine operates in a cycle between temperatures 700 K and 400 K. The heat input to the engine during each cycle is 2800 J. What is the maximum possible work done by the engine in each cycle? (A) 1200 J (B) 1600 J (C)

    asked by Kate on March 6, 2010
  5. thermodynamics

    If a carnot engine receives heat from a heat source and discharge 1000J to a heat sink at temperature of 27C in each cycle, calculate the heat received and the work performed by the engine in each cycle

    asked by hiqk on April 28, 2013
  6. physics

    A Carnot engine is operated between two heat reservoirs at temperatures 520 K and 300 K. (a) If the engine receives 6.45 kJ of heat energy from the reservoir at 520 K in each cycle, how many joules per cycle does it reject to the

    asked by Jen on December 2, 2007
  7. physics

    A Carnot engine is operated between two heat reservoirs at temperatures 520 K and 300 K. (a) If the engine receives 6.45 kJ of heat energy from the reservoir at 520 K in each cycle, how many joules per cycle does it reject to the

    asked by Jen on December 2, 2007
  8. physics

    A heat engine absorbs 848 J of energy per cycle from a high-temperature source. The engine does 417 J of work during each cycle, expelling 431 J as heat. What is the engine’s efficiency?

    asked by Anonymous on April 25, 2013
  9. Physics College

    A heat engine operates in a Carnot cycle between 78.0°C and 340°C. It absorbs 22,000 J of energy per cycle from the hot reservoir. The duration of each cycle is 3.00 s. (a) What is the mechanical power output of this engine?

    asked by Meena on March 10, 2015
  10. phy

    An engine absorbs 2000j of heat from a hot reservoir and expels 750j to a cold reservoir during each poerating cycle, (i)what is the efficiency of the engine (ii)How much work is done during the cycle? (iii)What is the power

    asked by kate on July 4, 2013

More Similar Questions