MATH

A pharmacist mixed some 10%-saline solution
with some 15%-saline solution to obtain 100 mL of a 12%-saline solution. How much of the 10%-saline solution did the pharmacist use in the mixture?
A 60 mL
B 45 mL
C 40 mL
D 25 mL CAN SOME GIVE AN EQUATION TO HELP MY SOLVE THIS PROBLEM THIS IS THE ONLY WAY TO SOLVE THis problem

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  1. x ml of 10% --->0.1 x salt
    (100-x ml) of 15% ----> 0.15(100-x) salt

    total salt = .1x + 15 - .15x = 15-.05x salt
    so
    15-.05x = .12(100) = 12
    3 = .05x
    x = 60 ml

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