# Chemistry

Calculate the molality of 6.00 M H2SO4 solution. The density of the solution is 1.34 g/mL.

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1. 6.00 M is 6.00 moles/L of soln.
That is 6 moles x (98 g/mol) = 588 grams H2SO4 in the liter of soln..
Take 1 L of the solution. That will have a mass of volume x density = 1000 mL x 1.34 g/mL = 1340 grams. How much is H2SO4 and how much water. There are 588 grams H2SO4; therefore, 1340 g-588 = 752 g H2O.
molality = mols/kg solvent. You know moles H2SO4. You know kg solvent. You finish.

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posted by DrBob222
2. 7.98?

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posted by Kari
3. Yes, but check all my math leading up to that last step.

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posted by DrBob222

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