Math - another question

"In the expansion of (2-ax)^5 the coefficient of x^2 is 5. Find the value of a".

I know I have to use the binomial theorem to help me, but I don't know how.

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asked by Stuck
  1. I got it. :)

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    posted by Stuck
  2. How did u get it?

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  3. According to the binomial theorem, the term with x^2 would be the third term. I plugged my known values into the "formula" for the third term, and made it equal to 5. Then I solved for a. Sorry, my explanation is kind of vague.

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    posted by Stuck
  4. Cool, I appreciate you responding to my question.

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