A computer transmits 11 Web pages in 4 seconds to a Web server. A second computer transmits 33 pages in 8 seconds to the server. Are these two computers transmitting at the same speed?
no they are not, the second one is transmitting more than the first one. in 8 seconds the first one will transmitt 22, where in 8 seconds the second one will transmit 33.
How did you come up with that? I don't get how you did the math to it? Can you show me how?
#1. (11 pages/4 sec) x 8 sec = 22 pages.
#2 33 pages/8 sec x 8 sec - 33 pages.
ohhh ok...now I get it thanks! I just couldn't picture it :)
I remember that math question from Axia... MAT 115 final.
I remember that math question from Axia... MAT 115 final. That was an easy A.
To determine if the two computers are transmitting at the same speed, we can calculate their transmission rates.
Transmission rate, also known as data transfer rate, measures how much data can be transmitted per unit of time. It is typically measured in bits per second (bps) or bytes per second (Bps).
To calculate the transmission rate, we need to divide the number of pages transmitted by the time taken.
For the first computer:
Transmission rate = Number of pages transmitted / Time taken
Transmission rate = 11 pages / 4 seconds
Transmission rate = 2.75 pages per second
For the second computer:
Transmission rate = Number of pages transmitted / Time taken
Transmission rate = 33 pages / 8 seconds
Transmission rate = 4.125 pages per second
From the calculations, we can see that the first computer has a transmission rate of 2.75 pages per second, while the second computer has a transmission rate of 4.125 pages per second. Therefore, they are transmitting at different speeds.
In conclusion, the two computers are not transmitting at the same speed.