Math

Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve.

x = sec Q
y = cos Q

x^2 + y^2 = 1/cos^2 + sin^2/cos^2 =
x^2(1 +sin^2) = x^2(2-cos^2)

x^2(2-1/x^2) = 2x^2 - 1

x^2 - y^2 = 1

My teacher said to use secant*cosine = 1. Please explain!!

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asked by Abbey
  1. Isn't sec x = 1/cosx ??

    so isn't (secQ)(cosQ)
    = (1/cosQ)(cosQ) = 1 ???

    so we know
    secQ(cosQ) = 1
    xy=1

    looks like we got our equation!

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    posted by Reiny

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