Calculate the molarity and mole fraction of a 2.35 m solution of acetone (CH3COCH3) dissolved in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the final volume equals the sum of the volumes of acetone and ethanol.

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  1. 2.35 m.
    Take enough solution to have 2.35 moles. That mans you have 1 kg solvent (ethanol).
    volume ethanol = m/d = 1000g/0.789 = ??.
    2.35 mol acetone x molar mass acetone = grams acetone and mass/density = volume.
    Add volume acetone to volume ethanol to find total volume.
    Then 2.35 moles/L = M

    For mole fraction.
    moles acetone/total moles.
    Check my work.

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  2. m doesn't stand for moles. it stands for molality. molality is moles of solute divided by kiligrams of solvent. that might be your problem.

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