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The graph of the function y=x^3+12x^2+15x+3 has a relative maximum at x=

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asked by AKilah
  1. Set the derivative equal to zero.

    y' = 3x^2 + 24x +15 = 0
    x^2 +8x +5 = 0
    x = (1/2)[-8 + sqrt34]
    or
    x = (1/2)[-8 - sqrt34]

    There are two solutions. Pick the one for which the second derivative is negative.

    Only one of them works.

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    posted by drwls

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