2x + 3y = -13 4x + y = -1
School subject = math, not North Hall.
To solve the system of equations:
2x + 3y = -13 (Equation 1)
4x + y = -1 (Equation 2)
There are various methods you can use, such as substitution, elimination, or graphing. Let's use the substitution method.
Step 1: Solve one of the equations for a variable in terms of the other variable. In this case, let's solve Equation 2 for y:
y = -4x - 1
Step 2: Substitute the value of y in Equation 1 with the expression we obtained in Step 1:
2x + 3(-4x - 1) = -13
Step 3: Simplify the equation by distributing the 3:
2x - 12x - 3 = -13
Step 4: Combine like terms:
-10x - 3 = -13
Step 5: Move the constant term to the other side of the equation by adding 3 to both sides:
-10x = -10
Step 6: Solve for x by dividing both sides by -10:
x = -10 / -10
x = 1
Step 7: Substitute the value of x back into either equation to find the value of y. Let's use Equation 2:
4(1) + y = -1
Step 8: Simplify the equation:
4 + y = -1
Step 9: Move the constant term to the other side of the equation by subtracting 4 from both sides:
y = -1 - 4
y = -5
Therefore, the solution to the system of equations 2x + 3y = -13 and 4x + y = -1 is x = 1 and y = -5.