trig

Please help me solve this problem. I have a test tomorrow and I do not understand at all.

Determine all solutions of the equations in radians.

Find cos x/2, given that cos x = 1/4 and x terminates in 0 < x < π/2.

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asked by Mandy
  1. let's use
    cos 2A = 2cos^2 A - 1
    or
    cos x = 2cos^2(x/2) - 1
    1/4 = 2cos^2(x/2) - 1
    5/8 = cos^2(x/2)
    cosx = √5/√8 or √10/4

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    posted by Reiny
  2. How did you get 5/8? Thanks for your help!

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    posted by Mandy
  3. from
    1/4 = 2cos^2(x/2) - 1
    1/ 4 + 1 = 2cos^2(x/2)
    5/4 = 2cos^2(x/2) , now divide by 2
    5/8 = cos^2(x/2) , now take √
    cos x/2 = √5/√8 , rationalizing
    cos x/2 = (√5/√8)(√8/√8) = √40/8 = 2√10/8 = √10/4

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    posted by Reiny

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