# Physic

If you shout across a canyon and hear the echo 0.57 s later, how wide is the canyon?

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1. 2*Width = (sound speed)*(0.57 s)

The sound speed depends upon temperature but is about 340 m/s
Solve for the width. I hope you see why the factor 2 is needed.

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posted by drwls
2. 96.9

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posted by jgdc

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