Calculate the cell potential of a cell operating with the following reaction at 25°C, in which [Cr2O72‾ ] = 0.030 M, [I ‾ ] = 0.020, M, [Cr3+ ] = 0.20 M, and [H+ ] = 0.60 M.
Cr2O72-(aq) + 6 I ‾(aq) + 14 H+(aq) → 2Cr3+(aq) + 3 I2(s) + 7 H2O(l)

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  1. Write the balanced equation.
    Calculate Eocell.

    Then Ecell = Eocell - (0.0592/n)*log Q

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