Math

When trying to solve
arctan(sqrt 567.2 / -459.6) my answer was -2.96. My teacher said that i handled the radical wrong. She said I have to square both numbers, then add them, and then find the square root. I am confused because you cannot take the square root of -459.6. Please explain.

  1. 👍 0
  2. 👎 0
  3. 👁 80
  1. Im not sure by your equation why you are to follow that process, but if you are to first square the two numbers then you get rid of the -ve

    ie:

    567.2^2 and (-459.6)^2

    i hope this helps

    1. 👍 0
    2. 👎 0
    posted by lauren
  2. arctan(sqrt 567.2 / -459.6)
    = arctan(23.81596/-459.6)
    = arctan(-.051819)
    = -2.97°

    most calculators have been programmed that for any arc(trig function) they will give you the smallest value of rotation from 0,
    so -2.97 would be in the 4th quadrant, coterminal with 360-2.97 or 357.03°

    the tangent is also negative in the 2nd quadrant, so
    the smallest positive answer is 180-2.97 = 177.03°

    check: tan 357.03 = tan 177.03 = .05188
    √567.2/-459.6 = .0518189 , close enough,

    1. 👍 0
    2. 👎 0
    posted by Reiny

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus

    1.Evaluate: (1/(x*sqrt(x^2-4)) I know the answer is -1/2*arctan(2/sqrt(x^2-4)), but I am having trouble getting to this answer on my own. I know the formula to solve it is 1/a*arctan(x/a) and that a=2, but that's all I know.

    asked by Sandy on February 6, 2009
  2. calculus

    Let f be a function defined by f(x)= arctan x/2 + arctan x. the value of f'(0) is? It's 3/2 but I am not very clear on how to obtain the answer. I changed arctan x/2 into dy/dx=(4-2x)/(4sqrt(4+x^2)) but that's as far as I got.

    asked by Jamie on January 16, 2007
  3. PreCalculus

    I'm unsure how to even start this problem Solve for x: Arctan( -4/5 ) + Arcos (2/SQRT(5) ) = Arctan(x)

    asked by Kate on March 9, 2010
  4. Algebra

    Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now

    asked by Jamie on August 17, 2006
  5. Math

    Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, arctan(1/2) So far I got the first two values, arctan(-sqrt3), and that's 150 degrees. Arctan 0 would be zero degrees. I'll use just one answer for now, but

    asked by Anonymous on August 13, 2009
  6. algebra

    18 + sqrt567 ----------- 9 567 = 81 x 7 Therefore sqrt 567 = 9 sqrt 7 your fraction therefore can be written 2 + sqrt 7

    asked by kris on June 29, 2007
  7. Trigonometry

    I need help with I just can't seem to get anywhere. this is as far as I have got: Solve for b arcsin(b)+ 2arctan(b)=pi arcsin(b)=pi-2arctan(b) b=sin(pi-2arctan(b)) Sub in Sin difference identity let 2U=(2arctan(b))

    asked by Jen on July 27, 2007
  8. some algebra help (radicals)

    I hope I am writing this down right.. I am trying to do some practice questions to learn 10^5 (sqrt)2y - 4^5 (sqrt)2y I am trying to figure out how to solve this They gave us some answers to choose from, but I am clueless on how

    asked by Cassie on May 6, 2007
  9. Math - check my answers :)

    1. Find the amplitude, if it exists, and the period of y=tan 1/4È Answer: No limits in amplitude, y=tanÈ/4 period is 4pi 2.Solve x = Arctan(-sqrt3) Work: Pythagorean theorem: sqrt(1^2+3)= sqrt4=2 in length. Triangle is 1, sqrt

    asked by Grace on January 30, 2009
  10. Inequality

    When I solve the inquality 2x^2 - 6 < 0, I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or - sqrt 3

    asked by Jen on November 5, 2006

More Similar Questions