hi! is there a way to find the local and absolute extreme values of the functions in the given interval by using the TI-83... just asking if not can someone help me figure this out please.... really appreciated :) f(x)=x^3-6x^2+9x+1 [2,4]
Hello! Yes, you can use the TI-83 calculator to find the local and absolute extreme values of a function in a given interval. To find the local and absolute extreme values of the function f(x) = x^3 - 6x^2 + 9x + 1 on the interval [2, 4], you can follow these steps:
Step 1: Enter the function into your TI-83 calculator. Press the "Y=" button, then type in the equation as follows: Y1 = X^3 - 6X^2 + 9X + 1.
Step 2: Graph the function. Press the "GRAPH" button to see the graph of the function on your calculator's screen.
Step 3: Locate the local extreme values. First, press the "2ND" button followed by the "TRACE" button. Then, choose the "Minimum" or "Maximum" option to search for the local extreme values. Now, move the cursor to the left of the first extreme point and press "ENTER". Next, move the cursor to the right of the first extreme point and press "ENTER". Repeat this process to find all the local extreme values in the interval [2, 4].
Step 4: Locate the absolute extreme values. To find the absolute extreme values, press the "2ND" button followed by the "TRACE" button. Then, choose the "Minimum" or "Maximum" option to search for the absolute extreme values. Move the cursor to the leftmost point of the interval [2, 4] and press "ENTER". Next, move the cursor to the rightmost point of the interval [2, 4] and press "ENTER".
By following these steps, you should be able to find the local and absolute extreme values of the function f(x) = x^3 - 6x^2 + 9x + 1 on the interval [2, 4].