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Chemistry
I forgot in my previous question to say 1014 millibars. The question is I live at 1014 millibars for barometric pressure and temp. is 61 degrees Fahrenheit. I have an imaginary balloon that contains 22 grams of CO2what is the 
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HelpI'm really confusedThe barometric pressure in my area is 1014 and the temperature is 61 degrees farhenheit. I am suppose to have an imaginary balloon that contains 22 grams of carbon dioxide. Calculate the volume in liters 
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I have to chane the barometric pressure in my area to ATM. We have to look at the U.S. Weather map that gives the barometric pressure. I live in an area that has shows 1016 for barometric pressure. First is 1016 in millibars or 
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Given a balloon you have at home, to determine the barometric pressure in your area. Record the pressure below. Your balloon contains 22 grams of Carbon dioxide. Use the following link to determine the temperature in your area. 
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I have a balloon that contains 22 grams of Carbon dioxide. The barometric pressure is 1019 millibars which I converted to 1.006 Atm and the temperature is 299 "K". What is the volume of balloon? I used the ideal gas law to find 
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The barometric pressure recorded by a weather balloon is 0.731 atmoshperes (atm). Express this barometric pressure in millimeters of mercury (mm Hg). 
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I have a balloon that contains 22 grams of Carbon dioxide. The barometric pressure is 1019 millibars which I converted to 1.006 Atm and the temperature is 299 "K". What is the volume of balloon? I used the ideal gas law to find 
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can you check my answers. 1. What is the corresponding barometric pressure values in mmHg if the barometric pressure is reported as: 29.7 inHg. = 754.38mmHg 31.8 inHg. = 807.72mmHg 26.4 inHg. = 670.56mmHg 22.1 inHg. = 561.34mmHg 
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can you check my answers. 1. What is the corresponding barometric pressure values in mmHg if the barometric pressure is reported as: 29.7 inHg. = 754.38mmHg 31.8 inHg. = 807.72mmHg 26.4 inHg. = 670.56mmHg 22.1 inHg. = 561.34mmHg