I am solving for linear equations and I'm wondering if I did Step 3 right..
3x-y=8
x-y=8
Step 1
3x-y=8
3x-y+y=8+y
3x=8+y
3x/3=8+y/3
x=(8+y/3)
Step 2
3(8+y/3)-y=8
8+y-y=8
8+2y=8
8+2y-8=8-8
2y=0
2y/2=0/2
y=0
Step 3
x=8+y(0)/3
x=2.6
What a hard way of doing it.
look at the second equation, it is very easy to solve for x
x = 8+y
now sub that into the first
3(8+y) - y = 8
24 + 3y - y = 8
2y = -16
y = -8
back in x = 8+y
x = 8+(-8) = 0
Your last two lines of step1 are wrong
should have been
3x/3=(8+y)/3
x=(8+y)/3
of course that makes all the statements is Step 2 incorrect.
To determine if you did Step 3 correctly, let's take a closer look at your calculations:
Step 1:
You correctly eliminated the variable 'y' in the first equation to solve for 'x'.
3x - y = 8
3x = 8 + y
x = (8 + y) / 3
Step 2:
In this step, you substituted the value of 'y' from the second equation into the first equation. However, you made an error when simplifying the equation.
3(8 + y/3) - y = 8
24 + 3y/3 - y = 8
24 + y - y = 8 (Here, you made an error while subtracting y/3)
24 = 8
It seems that there was a mistake while simplifying the equation. As a result, the equations you provided do not have a solution. Please double-check your calculations and ensure accuracy.