(p^2-7)(p+8)
Revlew FOIL method and attempt the work your self
Nice of you drwls.
Are you solving for p?
Or are you expanding?
Assuming you are expanding the equation:
p^3+8p^2-7p-56
Assuming you are solving for p, and the entire equation is equal to zero:
p=squareroot(7), p=-8
To simplify the expression (p^2-7)(p+8), we can use the distributive property of multiplication over addition. This property states that for any three numbers a, b, and c, a(b + c) = ab + ac.
In this case, we have (p^2-7)(p+8). To simplify, we will distribute the (p^2-7) to both terms inside the parentheses, which gives us:
(p^2-7)(p+8) = p^2(p+8) - 7(p+8)
Now, let's simplify each term separately:
1. Simplify p^2(p+8):
To multiply p^2 and (p+8), we will again use the distributive property. Therefore, p^2(p+8) = p^2 * p + p^2 * 8 = p^3 + 8p^2.
2. Simplify -7(p+8):
To multiply -7 and (p+8), we will again use the distributive property. Therefore, -7(p+8) = -7 * p - 7 * 8 = -7p - 56.
Now, let's put the simplified terms together:
p^2(p+8) - 7(p+8) = p^3 + 8p^2 - 7p - 56.
And that's the simplified form of the expression (p^2-7)(p+8).