math
 👍
 👎
 👁

 👍
 👎

 👍
 👎
Respond to this Question
Similar Questions

Algebra 2
How is the expression log 32  log 8 written as a single logarithm? log 4 log 8 log 24 log 40

Math
Let log 2 = a, log 3 = b and log 7 = c. Express the indicated logarithm in terms of a, b, and c. 1log3 5 (3 is the subscript of the log) ans:(1a)/b, i need someone to show me the step bcus my ans is different from the given ans.

Trigonometry
This is a logs question If u=x/y^2, which expression is equivalent to log u? 1) log x + 2 log y 2) 2(log x log y) 3) 2(log x + log y) 4) log x 2 log y

mathematics
given that log(6)/log(a) = p and log(108)/log(a) = q , express log(3)/log(a) in terms of p and q

Trigonometry
The expression log(x^n/ radical y)is equivalent to 1. n log x  1/2 log y 2. n log x 2 log y 3. log (nx)  log (1/2y) 4. log (nx)  log (2y)

math
Calculate without using tables or calculators log 450 and log 324 given log 2 =0.3010 and log 3 =0.4771

Math/trig
Log radical b/ a^2 is equivalent to 1) 1/2 log b + 1/2 log a 2) l/2 log b 2 log a 3) 2 log b  1/2 log a 4) 1/2logb/2 log a

math(Please help)
1) use the properties of logarithms to simplify the logarithmic expression. log base 10 (9/300) log  log 300 log 9 = 2 log 3 log 300 = log 3 + log 100 = log 3+2 I just do not know how to put these together now!

pre calculous
use the properties of logarithms to write the expression as a sum or difference of logarithms or multiples of logarithms. show your work ln x^2/y^3 Assuming x,y AND z are positive use properties of logariths to write the

Algebra
Express as a single logarithm and simplify: 2 log 3 + log (3x) – log x

Math
solve log(7x3)+2log(5)=2+log(x+3) I've attempted to do this question and I ended up with log(73)+log(5^2)log(x+3)=2 but I don't what to do next or whether I did something wrong.

Math
If ln a=2, ln b=3, and ln c=5, evaluate the following: (a) ln(a^−2/b^4c^−3)= .9524 (b) ln(√b^−4*c^1*a^−1)= 1.739 (c) ln(a^2b^4)/ln(bc)^−2= 42.39 (d) (ln(c^−1))*(ln(a/b^3))^−4= .03507 I am getting these answers
You can view more similar questions or ask a new question.