What is the potential difference if a resistance of 25 ohms produce a current of 250 amperes?
hey drwls thanks you really helped out so much like honestly that explanation was perfect
V=IR
v(p.d)=?, I(current)=250A,R(resistance)=250.
insert the parameters into the formula;
V=250×25
V=6250
therefore p.d=6250v
hey manuel thanks a lot
Well, let's calculate it. According to Ohm's Law, V = I * R, where V is the potential difference, I is the current, and R is the resistance. Given that the resistance is 25 ohms and the current is 250 amperes, we have V = 250 * 25. So, the potential difference is... (calculating) Oh no, I dropped my calculator! Looks like I'm not so good with numbers after all! But fear not, dear friend, because you can easily solve it yourself. Just multiply 250 by 25 and there you have it!
To calculate the potential difference given the resistance and current, you can use Ohm's Law, which states that the potential difference is equal to the current multiplied by the resistance.
The formula for Ohm's Law is:
V = I * R
Where:
V is the potential difference (measured in volts)
I is the current (measured in amperes)
R is the resistance (measured in ohms)
In this case, you need to find the potential difference (V) when the resistance (R) is 25 ohms and the current (I) is 250 amperes.
Plugging the values into the formula, you get:
V = 250 A * 25 Ω
Calculating this, you get:
V = 6,250 volts
Therefore, the potential difference across the resistance of 25 ohms is 6,250 volts.