A household bleach solution contains 5.25% (by mass) NaClO. How many moles of NaClO are needed to make 1000L of the solution? (density = 1.07g/mL)
You've omitted something from the problem. To make 1000 L of what kind of solution. And is that 1000 L or 1.000 L.
To determine the number of moles of NaClO needed to make 1000L of the solution, we need to follow these steps:
Step 1: Calculate the mass of NaClO in 1000L of the solution.
We know the concentration of NaClO in the solution is 5.25% by mass. Therefore, we can calculate the mass of NaClO using the density of the solution.
Density = mass/volume
Rearranging the formula, mass = density * volume
Given:
Density = 1.07 g/mL
Volume = 1000 L = 1000 * 1000 mL = 1,000,000 mL
So, mass = 1.07 g/mL * 1,000,000 mL = 1,070,000 g
Step 2: Calculate the moles of NaClO using its molar mass.
The molar mass of NaClO can be calculated by adding the atomic masses of its constituents:
Na (sodium) = 22.99 grams/mol
Cl (chlorine) = 35.45 grams/mol
O (oxygen) = 16.00 grams/mol
Molar mass of NaClO = 22.99 + 35.45 + 16.00 = 74.44 grams/mol
Step 3: Calculate the number of moles.
To calculate the number of moles, we will use the formula:
moles = mass / molar mass
Moles of NaClO = 1,070,000 g / 74.44 g/mol
Calculating this value, we find that the solution contains approximately 14,371 moles of NaClO.