chemistry

how many kilojoules of heat are absorbed when 1.00L of water is heated from 18 degrees celsius to 85 degrees celsius?

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  1. The mass of 1 liter of water is very close to 1 kg
    q = (specific heat)*(mass)*deltaT
    specific heat of water = 4.18kJ/kg.C
    q = (4.18kJ/kg.C)(1.00kg)(85ºC-18ºC)

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