# College Chemistry

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http://www.jiskha.com/display.cgi?id=1269192766

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posted by Ms. Sue
2. The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.80 x 10-2 at 500 K. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.

2NOCl(g) = 2NO(g)+Cl2(g)

2NO(g)+Cl2(g) = 2NOCl(g)

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3. The answer is just the reciprocal of the first Kp. So in your calculator type in 1/1.80e-2 and that will be your answer for the Kp of the second equation at the same temperature.
The answer will be (in scientific notation): 5.56e1

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