how many moles of hydrogen chloride would be needed to react completely with 15g of barium carbonate
equation is given:
BaCO3 + 2HCl to BaCl2 + H2O + CO2
Convert 15 g BaCO3 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles BaCO3 to moles HCl.
it would take 30 grams of HCl to react completely with BaCO3, since it's a 1 to 2 ratio
30 grams of HCl = 1 mole/36 grams
so it's .83 moles of HCl
Margaret gets an A for trying but an F for the answer. Chemicals react by moles, not by grams; therefore, it will NOT take 30 grams HCl nor will it take 0.83 moles HCl. The statement about it being a 1:2 ratio is correct.
To determine the number of moles of hydrogen chloride (HCl) required to react completely with 15g of barium carbonate (BaCO3), you need to use stoichiometry. The given balanced equation shows that 1 mole of BaCO3 reacts with 2 moles of HCl.
Here's how you can calculate the number of moles of HCl required:
Step 1: Calculate the molar mass of BaCO3 (barium carbonate).
- Ba: 1 atom * atomic mass of Ba (137.33 g/mol) = 137.33 g/mol
- C: 1 atom * atomic mass of C (12.01 g/mol) = 12.01 g/mol
- O3: 3 atoms * atomic mass of O (16.00 g/mol) = 48.00 g/mol
Total molar mass of BaCO3 = 137.33 g/mol + 12.01 g/mol + 48.00 g/mol = 197.34 g/mol
Step 2: Calculate the number of moles of BaCO3.
- Moles = Mass / Molar mass
- Moles = 15g / 197.34 g/mol ≈ 0.076 moles
Step 3: Use the mole ratio to determine the number of moles of HCl.
- According to the balanced equation, 1 mole of BaCO3 reacts with 2 moles of HCl.
- Moles of HCl = Moles of BaCO3 * (2 moles of HCl / 1 mole of BaCO3)
- Moles of HCl = 0.076 moles * 2 ≈ 0.152 moles
Therefore, approximately 0.152 moles of hydrogen chloride would be needed to react completely with 15g of barium carbonate.