If cos A-1=0, where 0<or= A< 2pi, then A=? The answer I got was pi/3,5pi/3. I don't know where I went wrong can you please help. thanks
cos(A) -1 = 0
or
cos(A) = 1
arccos(1) = A = 0
cot 17= 3.2709 what does tan of 73 equal
To solve the equation cos A - 1 = 0, we can rearrange the equation as follows:
cos A - 1 = 0
cos A = 1
The cosine function represents the x-coordinate of a point on the unit circle. When the cosine value is 1, it means the x-coordinate is 1, which occurs when the angle is 0 degrees or 2π radians.
However, we need to take into account the condition given: 0 ≤ A ≤ 2π. This means we only consider solutions within this range.
So, the possible values for A are:
A = 0
A = 2π
These are the only solutions that fulfill the original equation and also satisfy the given condition. Therefore, the answer is A = 0, 2π.
The answer you mentioned, π/3 and 5π/3, are not correct solutions because they do not satisfy the original equation.