when heated, sodium bicarbonate, NaHCO3, decomposes into sodium carbonate, Na2CO3, water, and carbon dioxide. If 5.00 g of NaHCO3 decomposes what is the mass of the carbon dioxide produced?
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To calculate the mass of carbon dioxide produced when 5.00 g of NaHCO3 decomposes, you need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the decomposition of sodium bicarbonate (NaHCO3) is:
2 NaHCO3 -> Na2CO3 + H2O + CO2
From the equation, you can see that for every 2 moles of NaHCO3, 1 mole of CO2 is produced. Now you need to calculate the number of moles of NaHCO3 in 5.00 g.
To calculate the number of moles, you can use the formula:
Number of moles = mass (in grams) / molar mass
The molar mass of NaHCO3 can be calculated by adding up the atomic masses of its constituent elements:
Na: 22.99 g/mol
H: 1.01 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
Molar mass of NaHCO3 = (22.99 + 1.01 + 12.01 + 3 × 16.00) g/mol = 84.01 g/mol
Now we can calculate the number of moles of NaHCO3:
Number of moles = 5.00 g / 84.01 g/mol
Next, use the stoichiometric ratio to find the number of moles of CO2 produced. From the balanced chemical equation, you know that 2 moles of NaHCO3 produce 1 mole of CO2.
Finally, you can calculate the mass of CO2 produced using the molar mass of CO2, which is 44.01 g/mol:
Mass of CO2 = Number of moles of CO2 × molar mass of CO2
By following these steps, you can determine the mass of carbon dioxide produced when 5.00 g of NaHCO3 decomposes.