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A spinner has regions numbered 1 through 21. What is the probability that the spinner will stop on an even number or a multiple of 3?

Okay so I am lost. I understand that the probability of an event is

the # of ways an event can occur over the total # of possible outcomes.

I need some explaining done. Please

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Carrie

  1. Would the total possible outcomes be 17?

    The number of evens would be 10 and the multiply of 3 is 7. So 10 and 7 together is 10.

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    Carrie

  2. List the numbers from 1 to 21 which are either even or multiples of 3:
    2,3,4,6,8,9,10,12,14,15,16,18,20,12

    I count 14, not 17.
    Prob(event as stated) = 14/21 = 2/3

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    Reiny

  4. Ok. I counted some numbers twice. I needed to write the numbers out like you did. Thanks

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    Carrie

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