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The following reaction is first order, C2H6==> 2CH3. If the rate constant is equal to 5.5 x 10-4 s^-1 at 1000 K, how long will it take for 0.35 mol of C2H6 in a 1.00 L container to decrease to 0.20 mol in the same container?

Thank you very much

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gaby

  1. ln(No/N) = kt
    ln(0.35/0.20) = kt
    Substitute for k and calculate t. The calculated time will be in seconds.

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    DrBob222

  2. ln(No/N) = kt
    ln(0.35/0.20) = kt
    ln(0.35/0.20)=1000*t
    ln(0.35/0.20)/(1000)=5.59

    but that answer is not on my worksheet im i doing something wrong?

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    gaby

  4. I'm not surprised. Why did you substitute 1000 for k? The problem states k = 5.5 x 10^-4 s^-1. You substituted 1000 Kelvin which is the temperature.

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    DrBob222

  5. oh haha i didn't notice i feel now

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    gaby

  6. ok i got i now thank you very much

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    gaby

  8. Chalk it up to "not focused" and work on focusing on the work at hand.

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    DrBob222

  9. i am trying to find tis answer but I m getting different result

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    Alibaba

  10. ln(No/N)
    =ln(0.35/0.20)
    = 0.559
    0.559/5.5*10-4
    =1017.48
    =17mins

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    Anonymous

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